document.write( "Question 709256: how do I solve x + 7y = 39 and 3x - 2y = 2 by using substitution?
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Algebra.Com's Answer #436498 by checkley79(3341)\"\" \"About 
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x + 7y = 39
\n" ); document.write( "X=39-7Y
\n" ); document.write( "3x - 2y = 2
\n" ); document.write( "3(39-7Y)-2Y=2
\n" ); document.write( "117-21Y-2Y=2
\n" ); document.write( "-23Y=2-117
\n" ); document.write( "-23Y=-115
\n" ); document.write( "Y=-115/-23
\n" ); document.write( "Y=5 ANS.
\n" ); document.write( "X+7*5=39
\n" ); document.write( "X+35=39
\n" ); document.write( "X=39-35
\n" ); document.write( "X=4 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*4-2*5=2
\n" ); document.write( "12-10=2
\n" ); document.write( "2=2
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