document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709295>Question 709295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a rectangle are parallel to each other and are doneted as y. The other two sides of the rectangle are also parallel to each other and are denoted as x. If the sides x of the rectangle are increased by 3 units, the resulting figure is a square with area 20. What was the original area?\r<BR>\n" );
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document.write( "My attempt: y(x+3)=20<BR>\n" );
document.write( "             y=x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436496 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The original area is A = xy\r<BR>\n" );
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document.write( "The new area is y(x+3) = xy + 3y and this is equal to 20, so\r<BR>\n" );
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document.write( "xy + 3y = 20\r<BR>\n" );
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document.write( "We know that the new figure is a square, so y = x+3\r<BR>\n" );
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document.write( "Plug this in and solve for x \r<BR>\n" );
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document.write( "xy + 3y = 20\r<BR>\n" );
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document.write( "x(x+3) + 3(x+3) = 20\r<BR>\n" );
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document.write( "x^2 + 3x + 3x + 9 = 20\r<BR>\n" );
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document.write( "x^2 + 6x + 9 - 20 = 0\r<BR>\n" );
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document.write( "x^2 + 6x - 11 = 0\r<BR>\n" );
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document.write( "Now use the quadratic formula to solve for x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3%2B2%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"x+=+-3%2B2%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3-2%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"x+=+-3-2%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+1.472136 ALIGN=MIDDLE  ALT=\"x+=+1.472136\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-7.472136 ALIGN=MIDDLE  ALT=\"x+=+-7.472136\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Note: Solutions above are approximate\r<BR>\n" );
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document.write( "Ignore the negative solution\r<BR>\n" );
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document.write( "So x is roughly 1.472136 and y = x+3 = 1.472136+3 = 4.472136\r<BR>\n" );
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document.write( "So x = 1.472136 and y = 4.472136\r<BR>\n" );
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document.write( "The area of the original rectangle is therefore\r<BR>\n" );
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document.write( "A = xy\r<BR>\n" );
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document.write( "A = 1.472136*4.472136\r<BR>\n" );
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document.write( "A = 6.583592402496\r<BR>\n" );
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document.write( "So the area of the original rectangle is roughly 6.583592402496 square units. </SPAN>\n" );
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