document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709178>Question 709178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "The ratio of the length and breadth of a plot is 4 : 5. I f the length is 20 m less than the breadth, what<BR>\n" );
document.write( "is the perimeter of the plot?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436424 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4:5=(X-20):X CROSS MULTIPLY.<BR>\n" );
document.write( "5(X-20)=4X<BR>\n" );
document.write( "5X-100=4X<BR>\n" );
document.write( "5X-4X=100<BR>\n" );
document.write( "X=100 ANS FOR THE LONGER SIDE.<BR>\n" );
document.write( "100-20=80 FOR THE SHORTER SIDE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4/5=80/100<BR>\n" );
document.write( "4/5=4/5<BR>\n" );
document.write( "PERIMETER=2L+2W<BR>\n" );
document.write( "P=2*80+2*100<BR>\n" );
document.write( "P=160+200<BR>\n" );
document.write( "P=360m. ANS. </SPAN>\n" );
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