document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709144>Question 709144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is 2^-3=.125 in log form\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436404 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%282%2C.125%29 ALIGN=MIDDLE  ALT=\"log%282%2C.125%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  (that is, log base 2 of .125)<BR>\n" );
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