document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=709063>Question 709063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the diagonal of a rectangle has length 14 feet, and the area of the rectangle is 64 square feet, find the number of feet in the perimeter of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436361 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the diagonal of a rectangle has length 14 feet, and the area of the rectangle is 64 square feet, find the number of feet in the perimeter of the rectangle.<BR>\n" );
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document.write( "Draw a rectangle with one diagonal.<BR>\n" );
document.write( "Let the sides be L and W<BR>\n" );
document.write( "Then diagonal = sqrt[L^2+W^2]<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "sqrt(L^2+W^2) = 14 ft.<BR>\n" );
document.write( "L^2 + W^2 = 196<BR>\n" );
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document.write( "LW = 64 sq. ft<BR>\n" );
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document.write( "L = 64/W<BR>\n" );
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document.write( "Substitute for \"L\" and solve for \"W\":<BR>\n" );
document.write( "(64/W)^2 + W^2 = 196<BR>\n" );
document.write( "64 + W^4 = 196W^2<BR>\n" );
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document.write( "W^4 - 196W^2 + 64 = 0<BR>\n" );
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document.write( "W^2 = 195.67<BR>\n" );
document.write( "W = 13.99 ft<BR>\n" );
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document.write( "Solve for L:<BR>\n" );
document.write( "L = 64/W<BR>\n" );
document.write( "L = 64/13.99<BR>\n" );
document.write( "L = 4.57 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=================<BR>\n" );
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