document.write( "Question 708337: Construct a difference table to predict the next term of the sequence.
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document.write( "3, −2, 0, 15, 49, 108, . . . \n" );
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Algebra.Com's Answer #436358 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Too late probably, but here's what I would do. \n" ); document.write( "I would put those numbers in a column, like this: \n" ); document.write( "3 \n" ); document.write( "-2 \n" ); document.write( "0 \n" ); document.write( "15 \n" ); document.write( "49 \n" ); document.write( "108 \n" ); document.write( "I would make a second column with the differences. \n" ); document.write( "subtract the first number from the second, the second number from the third, and so on. \n" ); document.write( "-2-3=-5 \n" ); document.write( "0-(-2)=2 \n" ); document.write( "15-0=15 \n" ); document.write( "49-15=34 \n" ); document.write( "108-49=59 \n" ); document.write( "Since I see no pattern in those differences, \n" ); document.write( "I would make a third column with the differences of those differences: \n" ); document.write( "2-(-5)=7 \n" ); document.write( "15-2=13 \n" ); document.write( "34-15=19 \n" ); document.write( "59-34=25 \n" ); document.write( "Then I would calculate differences of differences of differences for a fourth column: \n" ); document.write( "13-7=6 \n" ); document.write( "19-13=6 \n" ); document.write( "25-19=6 \n" ); document.write( "It could look like this: \n" ); document.write( "...3...-5....7...6 \n" ); document.write( "..-2....2...13...6 \n" ); document.write( "...0...15...19...6 \n" ); document.write( "..15...34...25 \n" ); document.write( "..49...59 \n" ); document.write( ".108 \n" ); document.write( "Finally, I see a pattern. \n" ); document.write( "All the numbers in the fourth column are 6. there would be more 6's if we continue the pattern. \n" ); document.write( "The numbers on the third column were increasing by 6 as they went down. \n" ); document.write( "The number after 25 would have been 25+6=31. \n" ); document.write( "The numbers in the second column increased by adding the number from the third column. \n" ); document.write( "-5+7=2 \n" ); document.write( "2+15=15 \n" ); document.write( "15+19=34 \n" ); document.write( "34+25=59 \n" ); document.write( "That means that the number after 59 would be 59+31=90. \n" ); document.write( "the numbers in the first column were calculated the same way using the second column: \n" ); document.write( "15+34=49 \n" ); document.write( "49+59=108 \n" ); document.write( "What comes next is \n" ); document.write( "108+90=198 \n" ); document.write( "The next number in the sequence is \n" ); document.write( "The table would be extended like this: \n" ); document.write( "...3...-5....7...6 \n" ); document.write( "..-2....2...13...6 \n" ); document.write( "...0...15...19...6 \n" ); document.write( "..15...34...25...6 \n" ); document.write( "..49...59...31...6 \n" ); document.write( ".108...90...37 \n" ); document.write( ".198..127 \n" ); document.write( ".325 \n" ); document.write( " |