document.write( "Question 708894: how to factor? -2x^2-3x+6 \n" ); document.write( "
Algebra.Com's Answer #436298 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"-2x%5E2-3x%2B6\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"-%282x%5E2%2B3x-6%29\" Factor out the GCF \"-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"2x%5E2%2B3x-6\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"2x%5E2%2B3x-6\", we can see that the first coefficient is \"2\", the second coefficient is \"3\", and the last term is \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"2\" by the last term \"-6\" to get \"%282%29%28-6%29=-12\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-12\" (the previous product) and add to the second coefficient \"3\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-12\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-12\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,12\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-12\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-12\".\r
\n" ); document.write( "\n" ); document.write( "1*(-12) = -12
\n" ); document.write( "2*(-6) = -12
\n" ); document.write( "3*(-4) = -12
\n" ); document.write( "(-1)*(12) = -12
\n" ); document.write( "(-2)*(6) = -12
\n" ); document.write( "(-3)*(4) = -12\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"3\":\r
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First NumberSecond NumberSum
1-121+(-12)=-11
2-62+(-6)=-4
3-43+(-4)=-1
-112-1+12=11
-26-2+6=4
-34-3+4=1
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that there are no pairs of numbers which add to \"3\". So \"2x%5E2%2B3x-6\" cannot be factored.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"-2x%5E2-3x%2B6\" simply factors to \"-%282x%5E2%2B3x-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"-2x%5E2-3x%2B6=-%282x%5E2%2B3x-6%29\".
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