document.write( "Question 708854: A new automobile engine can run on a mixture of gasoline and a substitute fuel. If gas costs $2.48 per gallon and the substitute fuel cost $1.82 per gallon, what percent of a mixture must be a substitute fuel to bring down to $2.15 per gallon? \n" ); document.write( "
Algebra.Com's Answer #436294 by josgarithmetic(39618)\"\" \"About 
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\"What percent of the mixture\", means for 100 parts. First set up the cost equation.\r
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\n" ); document.write( "\n" ); document.write( "x and y, the gallons or just parts of each fuel to mix. x the fuel, y the substitute.\r
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\n" ); document.write( "\n" ); document.write( "\"2.48x%2B1.82y=2.15\" dollars (so this uses x and y as gallons). That is for 1 gallon of mixture.\r
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\n" ); document.write( "\n" ); document.write( "Since that was for just 1 gallon, we expect x+y=1. You can imagine the 1 as made of 100 equal parts; the gallon can be understood as divisible into 0.01 multiplied by 100.\r
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\n" ); document.write( "\n" ); document.write( "We just have this system:
\n" ); document.write( "\"2.48x%2B1.82y=2.15\"
\n" ); document.write( "\"x%2By=1\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply the second equation by 1.82, and subtract it from the first equation and get a value for x (after a little more arithmetic).\r
\n" ); document.write( "\n" ); document.write( "2.48x-1.82x+1.82y-1.82y=2.15-1.82(1)
\n" ); document.write( "0.66x=0.33
\n" ); document.write( "\"highlight%28x=0.5%29\"\r
\n" ); document.write( "\n" ); document.write( "That means y is also \"highlight%280.5%29\"\r
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\n" ); document.write( "\n" ); document.write( "ANSWER: Half gallon for each one to make 1 gallon of fuel mixture at 2.15 dollars per gallon. 50% of each fuel.\r
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