document.write( "Question 708854: A new automobile engine can run on a mixture of gasoline and a substitute fuel. If gas costs $2.48 per gallon and the substitute fuel cost $1.82 per gallon, what percent of a mixture must be a substitute fuel to bring down to $2.15 per gallon? \n" ); document.write( "
Algebra.Com's Answer #436294 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! \"What percent of the mixture\", means for 100 parts. First set up the cost equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x and y, the gallons or just parts of each fuel to mix. x the fuel, y the substitute.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since that was for just 1 gallon, we expect x+y=1. You can imagine the 1 as made of 100 equal parts; the gallon can be understood as divisible into 0.01 multiplied by 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We just have this system: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the second equation by 1.82, and subtract it from the first equation and get a value for x (after a little more arithmetic).\r \n" ); document.write( "\n" ); document.write( "2.48x-1.82x+1.82y-1.82y=2.15-1.82(1) \n" ); document.write( "0.66x=0.33 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That means y is also \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER: Half gallon for each one to make 1 gallon of fuel mixture at 2.15 dollars per gallon. 50% of each fuel.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |