document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708836>Question 708836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two number is 22.the sum of 3/4 one of the number and 1/5 of the other number is 11.find the two numbers?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436279 by </B><A HREF=/tutors/aboutme.mpl?userid=opeodu><B>opeodu(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=opeodu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=opeodu><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve any word problems. All you need do at first is to introduce a variable. In this case, two numbers are given so the variables are two in number. Let the first and second number be x & y respectively. x+y=22 3x/4+y/5=11 solving simultaneously (x+y)=22 15x+4y=220 4*--(x+y)=22 15x+4y=220 4x+4y=88 15x+4y=220 subtracting -11x=-132 x=12 substitute x into the first equation x+y=22 12+y=22 y=22-12=10 </SPAN>\n" );
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