document.write( "Question 62784: Can you please help me solve by using the subtitution and elimination method (unless there is no infnite number or solution.)
\n" ); document.write( "x + 2y = 6,
\n" ); document.write( "2x + y = 8 \n" ); document.write( "

Algebra.Com's Answer #43621 by jai_kos(139) $\"\"$ $\"About$

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x + 2y = 6 -->(1)
\n" ); document.write( "2x + y = 8-->(2)\r
\n" ); document.write( "\n" ); document.write( "Multiply equation(2) by 2, we get\r
\n" ); document.write( "\n" ); document.write( "2x + 4y = 12 -->(3)\r
\n" ); document.write( "\n" ); document.write( "Now subtract equation(3) with equation(2), we get\r
\n" ); document.write( "\n" ); document.write( "3y = 4
\n" ); document.write( "Now divide the above by 3, we get\r
\n" ); document.write( "\n" ); document.write( "y = 4/3\r
\n" ); document.write( "\n" ); document.write( "Now put this value in equation(2), we get
\n" ); document.write( "2x + (4/3) = 8\r
\n" ); document.write( "\n" ); document.write( "2x =8 -(4/3)\r
\n" ); document.write( "\n" ); document.write( "2x =20 /3\r
\n" ); document.write( "\n" ); document.write( "x = 20 /3 *2\r
\n" ); document.write( "\n" ); document.write( "x = 10/3\r
\n" ); document.write( "\n" ); document.write( "Hence the value of x =10/3 and y = 4/3\r
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