document.write( "Question 708648: A plant food is to be made from three chemicals. The combined amounts of the first two chemicals must be 80% of the resulting mix. The second and third chemical must be in the ratio 4 to 3 by weight. How much of each chemical is needed to make 700 kg of the plant food? \n" ); document.write( "
Algebra.Com's Answer #436198 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Use a, b, and c as the quantities each chemical. \n" ); document.write( "These initial equations can be made from the problem description:\r \n" ); document.write( "\n" ); document.write( "The total was to be 700 pounds, so \n" ); document.write( "The 80% requirement gives, \n" ); document.write( "The ratio information indicates, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rework the last two equations into these: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The system of equations to work with then is this one: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Matrix operations is the way to continue here, at least partly. \n" ); document.write( "That system can give us this matrix: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I briefly list the row operations but not here show the work. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now having b and c, the 700 summation equation can be used and b and c simply subsituted to find a (not continuing further with matrix operations). \n" ); document.write( "result for a: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER: |