document.write( "Question 708648: A plant food is to be made from three chemicals. The combined amounts of the first two chemicals must be 80% of the resulting mix. The second and third chemical must be in the ratio 4 to 3 by weight. How much of each chemical is needed to make 700 kg of the plant food? \n" ); document.write( "
Algebra.Com's Answer #436198 by josgarithmetic(39618)\"\" \"About 
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Use a, b, and c as the quantities each chemical.
\n" ); document.write( "These initial equations can be made from the problem description:\r
\n" ); document.write( "\n" ); document.write( "The total was to be 700 pounds, so \"a%2Bb%2Bc=700\".
\n" ); document.write( "The 80% requirement gives, \"%28a%2Bb%29%2F700=0.8\"
\n" ); document.write( "The ratio information indicates, \"b%2Fc=4%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Rework the last two equations into these:
\n" ); document.write( "\"a%2Bb=560\", and \"b-%284%2F3%29c=0\".\r
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\n" ); document.write( "\n" ); document.write( "The system of equations to work with then is this one:
\n" ); document.write( "\"a%2Bb%2Bc=700\"
\n" ); document.write( "\"a%2Bb=560\"
\n" ); document.write( "\"b-%284%2F3%29c=0\"\r
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\n" ); document.write( "\n" ); document.write( "Matrix operations is the way to continue here, at least partly.
\n" ); document.write( "That system can give us this matrix:
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\n" ); document.write( "\n" ); document.write( "I briefly list the row operations but not here show the work.
\n" ); document.write( "\"R%5B1%5D-R%5B2%5D=+R%5B2%5D\", immediately giving \"c=140\".
\n" ); document.write( "\"R%5B3%5D%2B%284%2F3%29R%5B1%5D=R%5B3%5D\", giving b=186 2/3, \"b=186%262%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Now having b and c, the 700 summation equation can be used and b and c simply subsituted to find a (not continuing further with matrix operations).
\n" ); document.write( "result for a: \"a=373%262%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "ANSWER: \"a=373%261%2F3\", \"b=186%262%2F3\", \"c=140\", all in pounds.
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