document.write( "Question 708649: How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 60% antifreeze?\r
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document.write( "x= 70% antifreeze
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document.write( "x+70= 25%antifreeze\r
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document.write( "x+.60(x+70)=unknown this is were I am lost
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document.write( "x+.60x+42
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document.write( "1.6x+42 \n" );
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Algebra.Com's Answer #436196 by josgarithmetic(39799) ![]() You can put this solution on YOUR website! Taking the format of quantity*concentration,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Known also is that this starts with 70 gallons of one of the antifreeze solutions, so, \n" ); document.write( "x+70=V, which we might have used already in setting up the \"60%\" equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's do that, already: \n" ); document.write( " \n" ); document.write( "THAT is what we want to solve; solve for x. \n" ); document.write( " |