document.write( "Question 708649: How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 60% antifreeze?\r
\n" ); document.write( "\n" ); document.write( "x= 70% antifreeze
\n" ); document.write( "x+70= 25%antifreeze\r
\n" ); document.write( "\n" ); document.write( "x+.60(x+70)=unknown this is were I am lost
\n" ); document.write( "x+.60x+42
\n" ); document.write( "1.6x+42
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Algebra.Com's Answer #436196 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
Taking the format of quantity*concentration,\r
\n" ); document.write( "\n" ); document.write( "\"x%2A70%2B70%2A25\" = actual antifreeze substance\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2A70%2B70%2A25%29%2FV=60\", the desired concentration is 60%. Volume V is still unknown.\r
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\n" ); document.write( "\n" ); document.write( "Known also is that this starts with 70 gallons of one of the antifreeze solutions, so,
\n" ); document.write( "x+70=V, which we might have used already in setting up the \"60%\" equation.\r
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\n" ); document.write( "\n" ); document.write( "Let's do that, already:
\n" ); document.write( "\"%28x%2A70%2B70%2A25%29%2F%28x%2B70%29=60\"
\n" ); document.write( "THAT is what we want to solve; solve for x.
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