document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708611>Question 708611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a scientist has 35% acid solution and 20% acid solution and she needs 3 liters of 25% acid solution write and solve a linear equation and how much of each solution she should use. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436172 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a scientist has 35% acid solution and 20% acid solution and she needs 3 liters of 25% acid solution write and solve a linear equation and how much of each solution she should use.<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acis<BR>\n" );
document.write( "0.35x + 0.20(3-x) = 0.25*3<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "35x + 20*3 - 20x = 25*3<BR>\n" );
document.write( "15x = 5*3<BR>\n" );
document.write( "x = 1 liter (amt. of 35% solution needed)<BR>\n" );
document.write( "-------------------------------<BR>\n" );
document.write( "3-x = 2 liters (amt. of 20% solution needed)<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );