document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708574>Question 708574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this problem step by step please<BR>\n" );
document.write( "-6[16a-8(2a-2)] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436170 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -6[16a-8(2a-2)]<BR>\n" );
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document.write( "Start with the inside brackets, distribute the -8 and you have (-*- = +)<BR>\n" );
document.write( "-6(16a - 16a + 16)<BR>\n" );
document.write( "16a's are eliminated<BR>\n" );
document.write( "-6(16) = -96 <BR>\n" );
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