document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708220>Question 708220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the inverse of this function:\r<BR>\n" );
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document.write( "f(x)=log(2x)+3<BR>\n" );
document.write( "Here's what I've done. I'm not sure what to do next:<BR>\n" );
document.write( "x-3=log (2y)<BR>\n" );
document.write( "log (x-3)= log (2y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #436147 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=436147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the inverse of this function: <BR>\n" );
document.write( "f(x)=log(2x)+3<BR>\n" );
document.write( "interchange x and y<BR>\n" );
document.write( "x=log(2y)+3<BR>\n" );
document.write( "log(2y)=x-3<BR>\n" );
document.write( "convert to exponential form: base(10) raised to log of number(x-3)=number(2y)<BR>\n" );
document.write( "10^(x-3)=2y<BR>\n" );
document.write( "y^-1=10^(x-3)/2 </SPAN>\n" );
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