document.write( "Question 708332: I want to make 200 LIters of a 5% acid solution. If I have a 25% acid solution, how much water and how much of the 25% acid solution should I use? \n" ); document.write( "
Algebra.Com's Answer #436064 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
EDIT: Added explanation after the end.\r
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\n" ); document.write( "\n" ); document.write( "Water with \"nothing else\" in it will have 0% acid. You have 25% acid and you want to add water, of 0% acid to make 5% acid.\r
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\n" ); document.write( "\n" ); document.write( "How much acid will be?
\n" ); document.write( "How much volume of mixture will result?
\n" ); document.write( "What concentration of acid must result?
\n" ); document.write( "----------> Rational Equation:\r
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\n" ); document.write( "\n" ); document.write( "Let x be how much water
\n" ); document.write( "Let y be how much 25% acid\r
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\n" ); document.write( "\n" ); document.write( "\"%280%2Ax%2B25%2Ay%29%2F200=5\"
\n" ); document.write( "AND
\n" ); document.write( "\"x%2By=200\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for y in the rational equation. Use that result in the volume sum equation to find x.\r
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\n" ); document.write( "\n" ); document.write( "FURTHER EXPLANATION: The reason I said that last part is because \"0%2Ax=0\" in the rational equation. This means the rational equation only has one variable, the y. One single linear y, easy to solve. Then use the volume sum equation to find x.
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