document.write( "Question 708332: I want to make 200 LIters of a 5% acid solution. If I have a 25% acid solution, how much water and how much of the 25% acid solution should I use? \n" ); document.write( "
Algebra.Com's Answer #436064 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! EDIT: Added explanation after the end.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Water with \"nothing else\" in it will have 0% acid. You have 25% acid and you want to add water, of 0% acid to make 5% acid.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How much acid will be? \n" ); document.write( "How much volume of mixture will result? \n" ); document.write( "What concentration of acid must result? \n" ); document.write( "----------> Rational Equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be how much water \n" ); document.write( "Let y be how much 25% acid\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "AND \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for y in the rational equation. Use that result in the volume sum equation to find x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FURTHER EXPLANATION: The reason I said that last part is because |