document.write( "Question 708281: A projectile is launched from the ground with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet per seconds after launch is given by s = -16t^2 +V0t. Find the time(s) that the projectile will\r
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document.write( "(a) reach a height of 240ft and
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document.write( "(b) return to the ground when V0= 128 feet per second. \n" );
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Algebra.Com's Answer #436042 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(a) Set the function equal to 240.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute your given value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(b) Same as part (a) except you set the function equal to the height of the ground, i.e. zero. Your two zeros will be zero and some positive number. The zero root represents the instant of launch, and the other is the time of return to ground.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |