document.write( "Question 708103: How do u solve (2x+7)(3x-1)=0 \n" ); document.write( "
Algebra.Com's Answer #435988 by josgarithmetic(39617)\"\" \"About 
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This is an important rule to know:
\n" ); document.write( "If a is a real number, then a*0=0.\r
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\n" ); document.write( "\n" ); document.write( "This is another important thing to know:
\n" ); document.write( "If a and b are real number, and if a*b=0,
\n" ); document.write( "Then either a=0, or b=0, or both a and b are zero.\r
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\n" ); document.write( "\n" ); document.write( "Now, what can you do with those two binomial factors in your given equation?\r
\n" ); document.write( "\n" ); document.write( "Either [_____________] or [______________].\r
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\n" ); document.write( "\n" ); document.write( "Can 2x+7 be zero? How?
\n" ); document.write( "Can 3x-1 be zero? How?
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\n" ); document.write( "(Meaning, find x in each case.)
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