document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708112>Question 708112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kathy is 20 years older than Carol. In 6 years, the sum of their ages will be 50. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435983 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> k and c for kathy's age and carol's age NOW.\r<BR>\n" );
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document.write( "Now: k=c+20, which becomes k-c=20.\r<BR>\n" );
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document.write( "Six Years from Now:  (k+6)+(c+6)=50, from which<BR>\n" );
document.write( "k+c=50-12,<BR>\n" );
document.write( "k+c=38.\r<BR>\n" );
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document.write( "You have this system to solve:<BR>\n" );
document.write( "k-c=20, and k+c=38.\r<BR>\n" );
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document.write( "Various few simple ways to continue.  Try k=c+20, one of the original equations, and substitute into k+c=38..., solve for c... </SPAN>\n" );
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