document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708095>Question 708095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the inequalities, and express the solutions in terms of intervals<BR>\n" );
document.write( " 4/(6 - x) < 0  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435970 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6-x <> 0, so x<>+6.\r<BR>\n" );
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document.write( "Be sure you understand also that (+)/(+)>0, so you cannot allow 6-x to be positive.  What is next?  If 6-x can NOT be positive, then it MUST be negative.\r<BR>\n" );
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document.write( "Starting with the given, 4/(6 - x) < 0, and knowing 6-x must be negative,<BR>\n" );
document.write( "we have 6-x<0,<BR>\n" );
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document.write( "In interval notation, (6, +infinity). </SPAN>\n" );
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