document.write( "Question 708040: find A and B so that the system below has the solution (2,3)\r
\n" ); document.write( "\n" ); document.write( "Ax-2By=6
\n" ); document.write( "3Ax-By=-12\r
\n" ); document.write( "\n" ); document.write( "thanks for all the help :)
\n" ); document.write( "appriciate it
\n" ); document.write( "

Algebra.Com's Answer #435962 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Use the required point in both equations, simplify, and solve the resulting system.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A(2)-2B(3)=6
\n" ); document.write( "3A(2)-B(3)=-12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "System to solve, but...
\n" ); document.write( "2A-6B=6
\n" ); document.write( "6A-3B=-12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide the first by 2, and the second by 3:
\n" ); document.write( "System to solve:
\n" ); document.write( "A-3B=3
\n" ); document.write( "2A-B=-4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply all of the first by 2, subtract the second from the first:
\n" ); document.write( "\"highlight%28B=-2%29\", so you can pick any equation from the simplest system just found and find A. \"highlight%28A=-3%29\".
\n" ); document.write( "
\n" );