document.write( "Question 708059: in a chemistry lab, you have two vinegars. one is 5% acetic acid, and one is 6.5% acetic acid. you want to make 200 ml. of vinegar with 6% acetic acid. how many milliliters of each vinegar do you need to mix together?\r
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\n" ); document.write( "\n" ); document.write( "it would be greatly appreciated\r
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Algebra.Com's Answer #435958 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
With values like those, you should guess that you'll need a bit more than 100ml of the 6.5%, and a bit less than 100 ml. of the 5 %.\r
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\n" ); document.write( "\n" ); document.write( "x for 5% material, y for 6.5% material.\r
\n" ); document.write( "\n" ); document.write( "\"%285x%2B6.5y%29%2F200=6.0\"
\n" ); document.write( "\"5x%2B6.5y=1200\"\r
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\n" ); document.write( "\n" ); document.write( "Accounting for volumes to use, x+y=200.
\n" ); document.write( "You have a system:
\n" ); document.write( "\"5x%2B6.5y=1200\"
\n" ); document.write( "\"x%2By=200\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply the second entire equation by 5, and subtract the result from the first....
\n" ); document.write( "Get 1.5y=200, so y=133 plus 1/3 milliliters
\n" ); document.write( "\"y=133\" ml. of the 6.5% acetic acid vinegar.\r
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\n" ); document.write( "\n" ); document.write( "\"x=67\" ml. of the 5% material.
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