document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=708042>Question 708042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is too find y: (6/p)-ax=(m/y)+k I'm not sure where to start and need a bit of help to figure out where to go with this problem.\r<BR>\n" );
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document.write( "Thank you for the help\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435953 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think about undoing everything that was done to y.  Work from the outside inward.\r<BR>\n" );
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document.write( "(1)<BR>\n" );
document.write( "Add -k to both sides.\r<BR>\n" );
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document.write( "(2)<BR>\n" );
document.write( "Multiply both sides by (1/m).\r<BR>\n" );
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document.write( "See now you have some expression equals (1/y), so you really want the reciprocal of this.\r<BR>\n" );
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document.write( "(3)<BR>\n" );
document.write( "Invert left and right sides and simplify the left-hand expression.\r<BR>\n" );
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document.write( "Using symmetric property of equality, we want to manage <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2Fy%29=6%2F%28mp%29-ax%2Fm-k%2Fm ALIGN=MIDDLE  ALT=\"%281%2Fy%29=6%2F%28mp%29-ax%2Fm-k%2Fm\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Skipping the step, you should find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=mp%2F%286-axp-kp%29 ALIGN=MIDDLE  ALT=\"y=mp%2F%286-axp-kp%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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