document.write( "Question 708022: My problem is to find a: \"%28c%2Fx%29%2B%28m%2Fa%29=c\"
\n" ); document.write( "I've already distributed the problem to (ac+mx=acx) but I'm not sure where to go from here.\r
\n" ); document.write( "\n" ); document.write( "Thank you for the help
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Algebra.Com's Answer #435950 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
Starting with \"%28c%2Fx%29%2B%28m%2Fa%29=c\", \r
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\n" ); document.write( "\n" ); document.write( "For finding a,
\n" ); document.write( "notice a lowest common denominator of xa. Multiply left and right hand members by xa.\r
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\n" ); document.write( "\n" ); document.write( "\"xa%28c%2Fx%29%2Bxa%28m%2Fa%29=xac\"
\n" ); document.write( "\"ac%2Bxm=xac\"
\n" ); document.write( "\"ac%2Bxm=axc\" [commutative prop. multip.]
\n" ); document.write( "\"ac-ac%2Bxm=axc-ac\"
\n" ); document.write( "\"xm=a%28xc-c%29\"
\n" ); document.write( "\"xm%28xc-c%29%5E%28-1%29=a%28xc-c%29%28xc-c%29%5E%28-1%29\", [multiplicative inverse]
\n" ); document.write( "\"xm%2F%28xc-c%29=a%2A1\"
\n" ); document.write( "\"highlight%28a=xm%2F%28xc-c%29%29\"
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