document.write( "Question 707955: I have been wrestling with trying to solve this proof.....Pleeaaassseee HELP!
\n" ); document.write( "(J->L)->(M->N),A,A->(J->L),(M->N)->[(J->L)->O],O->(A->B)|-B\r
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Algebra.Com's Answer #435925 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You have A (ie you're assuming A is true) and you have this\r
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\n" ); document.write( "\n" ); document.write( "A -> (J -> L)\r
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\n" ); document.write( "\n" ); document.write( "So you can use modus ponens to get J -> L\r
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\n" ); document.write( "\n" ); document.write( "You have this statement\r
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\n" ); document.write( "\n" ); document.write( "(J->L)->(M->N)\r
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\n" ); document.write( "\n" ); document.write( "and you can use modus ponens with this and the \"J -> L\" you got earlier to get M -> N\r
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\n" ); document.write( "\n" ); document.write( "Now you have M -> N and (M->N)->[(J->L)->O]\r
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\n" ); document.write( "\n" ); document.write( "Use modus ponens to get (J->L)->O\r
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\n" ); document.write( "\n" ); document.write( "Then use modus ponens again with J -> L and (J->L)->O to get O\r
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\n" ); document.write( "\n" ); document.write( "You now have O and O -> (A -> B)\r
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\n" ); document.write( "\n" ); document.write( "Use modus ponens to get A -> B\r
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\n" ); document.write( "\n" ); document.write( "Finally, use modus ponens with A and A -> B to get B\r
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\n" ); document.write( "\n" ); document.write( "So all of the given statements and using modus ponens a bunch of times leads us to the conclusion of B\r
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\n" ); document.write( "\n" ); document.write( "This proves that the argument and conclusion is valid.
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