document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62759>Question 62759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> GIVE THE EQUATION FOR THE CIRCLE WITH CENTER C(3,-2) AND RADIUS 4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43592 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of the circle with centre C(3,-2) and radius 4 is given by:\r<BR>\n" );
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document.write( "(x-3)^2 + (y-(-2))^2 = 4^2\r<BR>\n" );
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document.write( "==> (x-3)^2 + (y+2)^2 = 16\r<BR>\n" );
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document.write( "On expanding we get,\r<BR>\n" );
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document.write( "x^2 - 6x + 9 + y^2 + 4y + 4 = 16\r<BR>\n" );
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document.write( "==> x^2 + y^2 - 6x + 4y + 13 = 16\r<BR>\n" );
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document.write( "==> x^2 + y^2 - 6x + 4y + 13 - 16 = 0 [adding - 16 to both the sides]\r<BR>\n" );
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document.write( "==> x^2 + y^2 - 6x + 4y - 3 = 0\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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