document.write( "Question 707942: factor the polynomial completely using the grouping method\r
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\n" ); document.write( "\n" ); document.write( "* what I've tried: 3b (3b - 8) + (16-a^2)
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Algebra.Com's Answer #435919 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
9b^2 - 24b + 16 - a^2\r
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\n" ); document.write( "\n" ); document.write( "(9b^2 - 24b + 16) - a^2\r
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\n" ); document.write( "\n" ); document.write( "(9b^2 - 12b - 12b + 16) - a^2\r
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\n" ); document.write( "\n" ); document.write( "((9b^2 - 12b) + (-12b + 16)) - a^2\r
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\n" ); document.write( "\n" ); document.write( "(3b(3b - 4) - 4(3b - 4)) - a^2\r
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\n" ); document.write( "\n" ); document.write( "(3b - 4)(3b - 4) - a^2\r
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\n" ); document.write( "\n" ); document.write( "(3b - 4)^2 - a^2\r
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\n" ); document.write( "\n" ); document.write( "(3b - 4 - a)(3b - 4 + a)\r
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\n" ); document.write( "\n" ); document.write( "So 9b^2 - 24b + 16 - a^2 completely factors to (3b - 4 - a)(3b - 4 + a)
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