document.write( "Question 707659: Please help me to prove that a, b, and c is odd (where) ax² + bx + c = 0
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Algebra.Com's Answer #435811 by MathLover1(20850) $\"\"$ $\"About$

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$\"ax%5E2+%2B+bx+%2B+c+=+0\"$ ....factor $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%28ax%2Bb%29+%2B+c+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "assume $\"a\"$ , $\"b\"$ , $\"c\"$ are all $\"odd\"$ , then for this $\"to\"$ $\"+have\"$ a solution, $\"x%28ax%2Bb%29\"$ must be $\"odd\"$ as $\"well\"$ \r
\n" ); document.write( "\n" ); document.write( "however,\r
\n" ); document.write( "\n" ); document.write( "if $\"x\"$ is $\"odd\"$ , $\"ax%2Bb\"$ is $\"even\"$ ; so, $\"x%28ax%2Bb%29\"$ is $\"even\"$ \r
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\n" ); document.write( "\n" ); document.write( "so, if $\"a\"$ , $\"b\"$ , $\"c\"$ are all $\"odd\"$ , there are $\"no\"$ $\"+possible\"$ $\"+solutions\"$ , the equation $\"ax%5E2%2Bbx%2Bc=0\"$ has $\"no\"$ $\"+rational\"$ $\"+roots\"$ \n" ); document.write( "

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