document.write( "Question 62751: Another one I'm stuck on help! A long document prints at a rate of 3 pages per minute. Twenty minutes later the same document is being printed out on a printer that prints at a rate of 5 pages per minute. How long will it take the second printer to catch up to the first printer.\r
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Algebra.Com's Answer #43581 by Edwin McCravy(20054) $\"\"$ $\"About$

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Another one I'm stuck on help! A long document prints at a rate of 3 pages per minute. Twenty minutes later the same document is being printed out on a printer that prints at a rate of 5 pages per minute. How long will it take the second printer to catch up to the first printer.
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document.write( "This is a DRT problem where D stands \r\n" );
document.write( "for Documents printed instead of Distance.\r\n" );
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document.write( "Make this chart:\r\n" );
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document.write( "                  D       R      T\r\n" );
document.write( "Slower printer  3(x+20)   3     x+20 \r\n" );
document.write( "Faster printer   5x       5      x\r\n" );
document.write( "\r\n" );
document.write( "                  D       R      T\r\n" );
document.write( "Slower printer                        \r\n" );
document.write( "Faster printer                      \r\n" );
document.write( "\r\n" );
document.write( "Fill in the rates as 3 pages per minute and\r\n" );
document.write( "5 pages per minute, respectively\r\n" );
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document.write( "                  D       R      T\r\n" );
document.write( "Slower printer            3          \r\n" );
document.write( "Faster printer            5        \r\n" );
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document.write( "Let x be the number of minutes it takes the\r\n" );
document.write( "second printer (the faster one) to catch up\r\n" );
document.write( "to the the 1st (the slower one). Fill that \r\n" );
document.write( "in.\r\n" );
document.write( "\r\n" );
document.write( "                  D       R      T\r\n" );
document.write( "Slower printer            3          \r\n" );
document.write( "Faster printer            5      x\r\n" );
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document.write( "Now since the slower printer has already\r\n" );
document.write( "been printing for 20 minutes before ths\r\n" );
document.write( "second one starts, its time is 20 minutes\r\n" );
document.write( "more than the second one.  So fill in\r\n" );
document.write( "x+20 for its time:\r\n" );
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document.write( "                  D       R      T\r\n" );
document.write( "Slower printer            3     x+20 \r\n" );
document.write( "Faster printer            5      x\r\n" );
document.write( "\r\n" );
document.write( "Now use D = RT to fill in the D's\r\n" );
document.write( "(numbers of documents printed)\r\n" );
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document.write( "                  D       R      T\r\n" );
document.write( "Slower printer  3(x+20)   3     x+20 \r\n" );
document.write( "Faster printer   5x       5      x\r\n" );
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document.write( "Now we are ready to make the equation.\r\n" );
document.write( "When the faster printer has caught up,\r\n" );
document.write( "the numbers of documents printed will\r\n" );
document.write( "be equal, so we set the two expressions\r\n" );
document.write( "for D equal:\r\n" );
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document.write( "     3(x + 20) = 5x\r\n" );
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document.write( "Solve that and get x = 30 minutes\r\n" );
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document.write( "Checking: Since the faster printer has \r\n" );
document.write( "been printing for 30 minutes at 5 pages \r\n" );
document.write( "per minute, it has printed 5×30 or 150\r\n" );
document.write( "pages.  The slower printer has been \r\n" );
document.write( "printing 20 minutes longer or 50 minutes,\r\n" );
document.write( "so it has printed 3×50 or 150 pages, also.\r\n" );
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document.write( "Edwin

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