document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62751>Question 62751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Another one I'm stuck on help!  A long document prints at a rate of 3 pages per minute.  Twenty minutes later the same document is being printed out on a printer that prints at a rate of 5 pages per minute.  How long will it take the second printer to catch up to the first printer.\r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43580 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the speed of the first printer = 3pages perminute\r<BR>\n" );
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document.write( "And the speed of the second printer = 5 pages permintue\r<BR>\n" );
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document.write( "We shall use the formula for the speed,\r<BR>\n" );
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document.write( "Speed of the first printer =  number of pages printed / time taken  \r<BR>\n" );
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document.write( "=> 3 = number of pages printed / 20 + t <BR>\n" );
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document.write( "   3 * (20 +t) = number of pages printed -->(1)\r<BR>\n" );
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document.write( "Speed of the second printer = number of pages printed / time taken\r<BR>\n" );
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document.write( "=> 5 = number of pages printed / t\r<BR>\n" );
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document.write( "   5 * t = number of pages printed -->(2)\r<BR>\n" );
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document.write( "Equating equation(1) and (2), we get\r<BR>\n" );
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document.write( "3(20 + t) = 5 * t\r<BR>\n" );
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document.write( "60 + 3t = 5t\r<BR>\n" );
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document.write( "60 = 5t - 3t\r<BR>\n" );
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document.write( "60 = 2t\r<BR>\n" );
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document.write( "60/2 = t\r<BR>\n" );
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document.write( "30 = t\r<BR>\n" );
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document.write( "Therefore it will take 30min for the second printer to catch up to the first printer. <BR>\n" );
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