document.write( "Question 707326: How would I solve this equation?\r
\n" ); document.write( "\n" ); document.write( "\"+sqrt+%28+4x%2B13+%29=+2x-1+\"
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Algebra.Com's Answer #435780 by vheroli(126)\"\" \"About 
You can put this solution on YOUR website!
\"+sqrt+%28+4x%2B13+%29=+2x-1+\"
\n" ); document.write( "\"++4x%2B13+=+%282x-1%29%5E2+\"
\n" ); document.write( "\"++4x%2B13+=+%282x-1%29%282x-1%29+\"
\n" ); document.write( "\"++4x%2B13+=++4x%5E2-4x%2B1++++\"
\n" ); document.write( "\"++4x%2B4x-4x%5E2+=++%2B1-13++++\"
\n" ); document.write( "\"++-4x%5E2%2B8x+=++-12++++\"
\n" ); document.write( "\"++-4x%5E2%2B8x%2B12+=0++++\"
\n" ); document.write( "\"++%28-4x%5E2%2B8x%2B12%29%2F4+=0%2F4++++\"
\n" ); document.write( "\"++-x%5E2%2B2x%2B3+=0++++\"\r
\n" ); document.write( "\n" ); document.write( "Factor out:
\n" ); document.write( "(-x+3)(x+1)
\n" ); document.write( "Thus:
\n" ); document.write( "First zero:
\n" ); document.write( "-x+3=0
\n" ); document.write( "-x=-3
\n" ); document.write( "x=3\r
\n" ); document.write( "\n" ); document.write( "Second Zero:
\n" ); document.write( "x+1=0
\n" ); document.write( "x=-1\r
\n" ); document.write( "\n" ); document.write( "
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