document.write( "Question 707572: a tree grows 1.5 meters during the first year of planting. During each subsequent year, the tree grows 9/10 of the previous year's growth. When the growth of the tree since planting is 11.35 meters, its age is? \n" ); document.write( "
Algebra.Com's Answer #435763 by josgarithmetic(39618)\"\" \"About 
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A formula has been developed for this. Terms being like a, ar, ar^2, ar^3,...
\n" ); document.write( "for n terms, the sum of those n terms is \"%28a-ar%5En%29%2F%281-r%29\".\r
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\n" ); document.write( "\n" ); document.write( "The problem description shows the sum (being 11.35), a=1.5, r=0.9, and the unknown variable is n for the number of years. You might first want to use the formula \"S%5Bn%5D=%28a-ar%5En%29%2F%281-r%29\", and solve for n. Once done that, THEN substitute the values. Working that way, you should get to
\n" ); document.write( "\"r%5En=%28a-S%281-r%29%29%2Fa\"; I am dropping the subscript on S just for convenience.\r
\n" ); document.write( "\n" ); document.write( "Taking logarithms of both sides whatever base you choose,
\n" ); document.write( "\"n%2Aln%28r%29=ln%28%28a-S%281-r%29%29%2Fa%29\"
\n" ); document.write( "\"n=ln%28%28a-S%281-r%29%29%2Fa%29%2Fln%28r%29\"\r
\n" ); document.write( "\n" ); document.write( "Now just substitute the values.
\n" ); document.write( "log base ten of [(1.5-11.35(1-.9))/1.5]=-0.6138
\n" ); document.write( "log base ten of 0.9=-.045757
\n" ); document.write( "n=13.4 years
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