document.write( "Question 707567: A chemist has two alloys, one of which is 15% gold and 25% lead and the other which is 40% gold and 30% lead. How many grams of each of the two alloys should be used to make an alloy that contains 76.5 g of gold and 116.5 g of lead? \n" ); document.write( "
Algebra.Com's Answer #435760 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Allow 1, x
\n" ); document.write( "Allow 2, y\r
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\n" ); document.write( "\n" ); document.write( "Accounting for the quantity of gold: 0.15x+0.40y=76.5 grams of Gold. Note this uses both alloys available, as does the next equation;\r
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\n" ); document.write( "\n" ); document.write( "Account for the quantity of lead: 0.25x+0.30y=116.5 grams Lead.\r
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\n" ); document.write( "\n" ); document.write( "System to start with is this:
\n" ); document.write( "\"0.15x%2B0.40y=76.5\"
\n" ); document.write( "\"0.25x%2B0.30y=116.5\"\r
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\n" ); document.write( "\n" ); document.write( "This will help to eliminate terms of y and to first solve for x.
\n" ); document.write( "3*(\"0.15x%2B0.40y=76.5\")
\n" ); document.write( "4*(\"0.25x%2B0.30y=116.5\")
\n" ); document.write( "Subtract one equation from the other.\r
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\n" ); document.write( "\n" ); document.write( "....and THIS may help to eliminate terms of x and solve for y.
\n" ); document.write( "5*(\"0.15x%2B0.40y=76.5\")
\n" ); document.write( "3*(\"0.25x%2B0.30y=116.5\")
\n" ); document.write( "Subtract one equation from the other.
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