document.write( "Question 707588: [(Sqrt2) secx-2](2sinx+1)=0
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document.write( "Find all solutions for this equation with the interval [0, 2pi) \n" );
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Algebra.Com's Answer #435751 by lwsshak3(11628) ![]() You can put this solution on YOUR website! [(Sqrt2) secx-2](2sinx+1)=0 \n" ); document.write( "Find all solutions for this equation with the interval [0, 2pi) \n" ); document.write( "** \n" ); document.write( "√2secx-2=0 \n" ); document.write( "√2secx=2 \n" ); document.write( "secx=2/√2 \n" ); document.write( "cosx=√2/2 \n" ); document.write( "x=π/4, 7π/4 ( In quadrants I and IV where sec and cos>0) \n" ); document.write( " |