document.write( "Question 707588: [(Sqrt2) secx-2](2sinx+1)=0
\n" ); document.write( "Find all solutions for this equation with the interval [0, 2pi)
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Algebra.Com's Answer #435751 by lwsshak3(11628)\"\" \"About 
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[(Sqrt2) secx-2](2sinx+1)=0
\n" ); document.write( "Find all solutions for this equation with the interval [0, 2pi)
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\n" ); document.write( "√2secx-2=0
\n" ); document.write( "√2secx=2
\n" ); document.write( "secx=2/√2
\n" ); document.write( "cosx=√2/2
\n" ); document.write( "x=π/4, 7π/4 ( In quadrants I and IV where sec and cos>0)
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