document.write( "Question 707434: Dale and Roger complete a job in 6 hours. It would take Dale 9 hours longer than Roger to do the job alone. How long would it take Roger alone? my teacher got 9hours but im not getting 9hrs. \n" ); document.write( "
Algebra.Com's Answer #435699 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Let x = time it takes for Roger to do the job alone\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So x+9 = time it takes for Dale to do the job alone\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/x + 1/(x+9) = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+9/(x(x+9)) + x/(x(x+9)) = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+9 + x)/(x(x+9)) = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2x+9)/(x(x+9)) = 1/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6(2x+9) = 1*x(x+9)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12x + 54 = x^2 + 9x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = x^2 + 9x - 12x - 54\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 3x - 54 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 9)(x + 6) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-9 = 0 or x+6 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 9 or x = -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ignore the negative answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Roger can do the job in 9 hours if he does it alone\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dale can do the job in 18 hours if he does it alone \n" ); document.write( " \n" ); document.write( " |