document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=707384>Question 707384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of water must be added to 80kg of a 60% iodine solution in order to dilute a 40% iodine solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435681 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of water must be added to 80kg of a 60% iodine solution in order to get a 40% iodine solution?<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "water + water = water<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "0.40*80 + 1*x = 0.60(80+x)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "40*80 + 100x = 60*80+ 60x<BR>\n" );
document.write( "40x = 20*80<BR>\n" );
document.write( "x = 40 kg (amt. of water to add)<BR>\n" );
document.write( "====================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );