document.write( "Question 707351: Solve the equation.\r
\n" ); document.write( "\n" ); document.write( "\"+1%5E3sqrt+%28+2x+%29=+1%5E3sqrt+%28+5x%2B2+%29+\"\r
\n" ); document.write( "\n" ); document.write( "Note: I apologize in advance, please ignore the 1's that are set in front of the cube square root. Thank you for your time.
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Algebra.Com's Answer #435666 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: you can type root(3,x+y) to mean \"root%283%2Cx%2By%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2C2x%29=root%283%2C5x%2B2%29\" ... Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28root%283%2C2x%29%29%5E3=%28root%283%2C5x%2B2%29%29%5E3\" ... cube both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x+=+5x%2B2\" ... cube the cube roots (notice they cancel out)\r
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\n" ); document.write( "\n" ); document.write( "I'm sure you know what to do from here.
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