document.write( "Question 707305: how do you solve b=4a+80 and b=1/2a+10 \n" ); document.write( "
Algebra.Com's Answer #435651 by stanbon(75887) ![]() You can put this solution on YOUR website! solve b=4a+80 and b=1/2a+10 \n" ); document.write( "----- \n" ); document.write( "Substitute and solve for \"a\": \n" ); document.write( "4a+80 = (1/2)a + 10 \n" ); document.write( "---- \n" ); document.write( "3.5a = -70 \n" ); document.write( "----- \n" ); document.write( "a = -20 \n" ); document.write( "================= \n" ); document.write( "Solve for \"b\": \n" ); document.write( "b = (1/2)a + 10 \n" ); document.write( "b = (1/2)(-20) + 10 \n" ); document.write( "b = -10 + 10 \n" ); document.write( "b = 0 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H, \n" ); document.write( "=================== \n" ); document.write( " |