document.write( "Question 707305: how do you solve b=4a+80 and b=1/2a+10 \n" ); document.write( "
Algebra.Com's Answer #435651 by stanbon(75887)\"\" \"About 
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solve b=4a+80 and b=1/2a+10
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\n" ); document.write( "Substitute and solve for \"a\":
\n" ); document.write( "4a+80 = (1/2)a + 10
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\n" ); document.write( "3.5a = -70
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\n" ); document.write( "a = -20
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\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "b = (1/2)a + 10
\n" ); document.write( "b = (1/2)(-20) + 10
\n" ); document.write( "b = -10 + 10
\n" ); document.write( "b = 0
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H,
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