document.write( "Question 707283: Algebra 1 problem using powers and exponents.\r
\n" ); document.write( "\n" ); document.write( "Someone offers to double the amount of money you have every day for 1 month (30 days). You have 1 nickel. On the first day, you will have 2 nickels worth $.10. On the second day, you will have 4 nickels worth $.20. How much money will you have on the 30th day?
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Algebra.Com's Answer #435636 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
This is essentially an exponential growth/decay problem. A general equation for these is:
\n" ); document.write( "\"A+=+A%5B0%5D%2Ar%5Et\"
\n" ); document.write( "where
\n" ); document.write( "t = number of units of time
\n" ); document.write( "A = the amount after t units of time
\n" ); document.write( "\"A%5B0%5D\" = the initial amount (IOW: The amount at t = 0)
\n" ); document.write( "r = the factor of change for 1 unit of time. If r > 1 then the equation is for growth and if 0 < r < 1 then the equation is for decay.

\n" ); document.write( "In your problem:
\n" ); document.write( "n = 30 days
\n" ); document.write( "r = 2 (since the amount doubles each day)
\n" ); document.write( "\"A%5B0%5D\" = 0.05
\n" ); document.write( "So your equation is:
\n" ); document.write( "\"A+=+0.05%2A2%5E30\"
\n" ); document.write( "Finding \"2%5E30\":
\n" ); document.write( "\"A+=+0.05%2A1073741824\"
\n" ); document.write( "Multiplying:
\n" ); document.write( "\"A+=+53687091.2\"
\n" ); document.write( "So after 30 days you will have $53,687,091.20 (Close to $54 million dollars!!)
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