document.write( "Question 707187: The length of a rectangle is 1m less than twice its width, and the area of the rectangle is 36m^2. Find the dimensions of the rectangle.
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Algebra.Com's Answer #435608 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
x(2x - 1) = 36\r
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\n" ); document.write( "\n" ); document.write( "2x^2 - x = 36\r
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\n" ); document.write( "\n" ); document.write( "2x^2 - x - 36 = 0\r
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\n" ); document.write( "\n" ); document.write( "(2x - 9)(x + 4) = 0\r
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\n" ); document.write( "\n" ); document.write( "2x-9 = 0 or x+4 = 0\r
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\n" ); document.write( "\n" ); document.write( "2x = 9 or x = -4\r
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\n" ); document.write( "\n" ); document.write( "x = 9/2 or x = -4\r
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\n" ); document.write( "\n" ); document.write( "x = 4.5 or x = -4\r
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\n" ); document.write( "\n" ); document.write( "Toss out the negative solution.\r
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\n" ); document.write( "\n" ); document.write( "So x = 4.5, 2x-1 = 2(4.5)-1 = 8\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the rectangle has a length of 8 m and a width of 4.5 m
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