document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=707260>Question 707260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lengths of the bases of a trapezoid are represented by 4x+3 and 6x-9. If the median of a trapezoid measures 32, find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435607 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (Base1 + Base2)/2 = Median ... ie if you average the base lengths, you get the median\r<BR>\n" );
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document.write( "(4x+3 + 6x-9)/2 = 32 ... plug in the known/given info and solve for x\r<BR>\n" );
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document.write( "4x+3 + 6x-9 = 32*2\r<BR>\n" );
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document.write( "4x+3 + 6x-9 = 64\r<BR>\n" );
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document.write( "10x-6 = 64\r<BR>\n" );
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document.write( "10x = 64+6\r<BR>\n" );
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document.write( "10x = 70\r<BR>\n" );
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document.write( "x = 70/10\r<BR>\n" );
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document.write( "x = 7\r<BR>\n" );
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document.write( "Answer: x = 7<BR>\n" );
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