document.write( "Question 707255: A $5000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%? \n" ); document.write( "
Algebra.Com's Answer #435605 by jim_thompson5910(35256)\"\" \"About 
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The $5,000 invested at 3.9% simple interest gets you 5000*0.039*1 = 195 dollars in interest alone.\r
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\n" ); document.write( "\n" ); document.write( "Some other amount, call it x dollars, is invested at 6.5% simple interest for a year. This x dollar investment at 6.5% simple interest will earn 195 dollars in interest alone because the problem states that the two investments earned the same amount of interest.\r
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\n" ); document.write( "\n" ); document.write( "I = Prt\r
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\n" ); document.write( "\n" ); document.write( "195 = x*0.065*1\r
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\n" ); document.write( "\n" ); document.write( "195 = 0.065x\r
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\n" ); document.write( "\n" ); document.write( "0.065x = 195\r
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\n" ); document.write( "\n" ); document.write( "x = 195/0.065\r
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\n" ); document.write( "\n" ); document.write( "x = 3000\r
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\n" ); document.write( "\n" ); document.write( "Which means that 3000 dollars was invested at 6.5% simple interest.
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