document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=707256>Question 707256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sides of a triangle are 5,6,and 10. Find the length of the shortest side of a similar triangle whose perimeter is 63. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435600 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the original triangle is 5+6+10 = 21\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you multiply this perimeter by 3 you get 3*21 = 63. If you don't know that 3*21 = 63, then you can see that 63/21 = 3. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Apply this same scaling to each side to get 5*3 = 15, 6*3 = 18, 10*3 = 30\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the similar triangle with side lengths 15, 18, 30 is a triangle that has a perimeter of 63.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The shortest side is therefore <font color=\"red\">15</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );