document.write( "Question 707225: please help me i greatly appreciate it:)\r
\n" ); document.write( "\n" ); document.write( "jacqui has grades of 77 and 76 on her first two algebra test.. if she wants an avg. of atleast 79, what possible scores can she make on her third test?
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Algebra.Com's Answer #435580 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "first test: \"77\"\r
\n" ); document.write( "\n" ); document.write( "second test: \"76\" \r
\n" ); document.write( "\n" ); document.write( "third test: \"x\"\r
\n" ); document.write( "\n" ); document.write( "she wants an avg. of at least \"79\"\r
\n" ); document.write( "\n" ); document.write( "so, \"%2877%2B76%2Bx%29%2F3=79\"\r
\n" ); document.write( "\n" ); document.write( "\"77%2B76%2Bx=79%2A3\"\r
\n" ); document.write( "\n" ); document.write( "\"153%2Bx=237\"\r
\n" ); document.write( "\n" ); document.write( "\"x=237-153\"\r
\n" ); document.write( "\n" ); document.write( "\"x=84\"....possible scores can she make on her third test are \"84\" or greater
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