document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=707180>Question 707180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435553 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 50% antifreeze?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "anti + anti = anti<BR>\n" );
document.write( "0.30*90 + 0.60x = 0.50(90+x)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "30*90 + 60x = 50*90 + 50x<BR>\n" );
document.write( "10x = 20*90<BR>\n" );
document.write( "x = 180 gallons (amt. of 60% mix to add)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );