document.write( "Question 707046: determine the value(s) of \"k\" for which there is one and only one real solution to the following quadratic: 10kx = -16x^2 - 25\r
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Algebra.Com's Answer #435526 by jsmallt9(3758)\"\" \"About 
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There will be one and only one real solution to a quadratic equation when the discriminant is zero. So let's start by putting the equation into standard form. Adding \"16x%5E2\" and 25 to each side:
\n" ); document.write( "\"16x%5E2%2B10kx%2B25=0\"
\n" ); document.write( "The discriminant, in general, is \"b%5E2-4ac\". Our \"a\" is 16, \"b\" is 10k and \"c\" is 25. So our discriminant is:
\n" ); document.write( "\"%2810k%29%5E2-3%2816%29%2825%29\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"100k%5E2-1200\"
\n" ); document.write( "We want this to be zero so:
\n" ); document.write( "\"100k%5E2-1200+=+0\"
\n" ); document.write( "Now we solve for k. Dividing both sides by 100:
\n" ); document.write( "\"k%5E2-12+=+0\"
\n" ); document.write( "Adding 12:
\n" ); document.write( "\"k%5E2+=+12\"
\n" ); document.write( "So \"k+=+sqrt%2812%29\" or \"k+=+-sqrt%2812%29\". These square roots simplify:
\n" ); document.write( "\"k+=+sqrt%284%2A3%29\" or \"k+=+-sqrt%284%2A3%29\"
\n" ); document.write( "\"k+=+sqrt%284%29%2Asqrt%283%29\" or \"k+=+-sqrt%284%29%2Asqrt%283%29\"
\n" ); document.write( "\"k+=+2%2Asqrt%283%29\" or \"k+=+-2%2Asqrt%283%29\"
\n" ); document.write( "These are the only possible values for k which will lead to one and only one real solution for x.
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