document.write( "Question 707091: one number is 7 less than the second number. twice the second number is 7 less than 5 times the first. find the smaller of the two. \n" ); document.write( "
Algebra.Com's Answer #435524 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
a is first number; b is second number.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "one number is 7 less than the second number. \"a=-7%2Bb\"
\n" ); document.write( "twice the second number is 7 less than 5 times the first. \"2b=-7%2B5a\"
\n" ); document.write( "find the smaller of the two.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Those two equations turn into system:
\n" ); document.write( "\"a-b=-7\"
\n" ); document.write( "\"5a-2b=7\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply first equation by 2 and subtract from the second equation.
\n" ); document.write( "\"2a-2b=-14\"
\n" ); document.write( "\"5a-2b=7\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5a-2b-(2a-2b)=7-(-14)
\n" ); document.write( "3a+0=+7
\n" ); document.write( "\"a=7%2F3\", same as \"a=2%261%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use a to find b. Using original first equation, a=-7+b, b=a+7,
\n" ); document.write( "b=7/3+7=\"9%261%2F3=b\"
\n" ); document.write( "
\n" );