document.write( "Question 706882: Larry's time to travel 250 miles is 2 hours more than Terrell's time to travel 165 miles. Terrell drove 5 miles per hour faster than Larry. How fast did each one travel? \n" ); document.write( "
Algebra.Com's Answer #435522 by ankor@dixie-net.com(22740)\"\" \"About 
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Larry's time to travel 250 miles is 2 hours more than Terrell's time to travel 165 miles.
\n" ); document.write( " Terrell drove 5 miles per hour faster than Larry.
\n" ); document.write( " How fast did each one travel?
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\n" ); document.write( "Let s = L's speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = T's speed
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "L's time - T's time = 2 hrs
\n" ); document.write( "\"250%2Fs\" - \"165%2F%28%28s%2B5%29%29\" = 2
\n" ); document.write( "multiply by s(s+5) to clear the denominators, resulting in
\n" ); document.write( "250(s+5) - 165s = 2s(s+5)
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\n" ); document.write( "250s + 1250 - 165s = 2s^2 + 10s
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\n" ); document.write( "85s + 1250 = 2s^2 + 10s
\n" ); document.write( "Combine on the right to form a quadratic equation
\n" ); document.write( "0 = 2s^2 + 10s - 85s - 1250
\n" ); document.write( "0 = 2s^2 - 75s - 1250
\n" ); document.write( "You can use the quadratic formula here, but this will factor to
\n" ); document.write( "(2s + 25)(s - 50) = 0
\n" ); document.write( "The positive solution is all we want here
\n" ); document.write( "s = 50 mph is L's speed
\n" ); document.write( "you can find T's speed
\n" ); document.write( ":
\n" ); document.write( "Check your solutions by finding the actual travel times of each.
\n" ); document.write( "See that they differ by 2 hrs
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