document.write( "Question 706989: How do I graph the relation 3y= 9x^2-6x+12? \n" ); document.write( "
Algebra.Com's Answer #435456 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! graph the relation 3y= 9x^2-6x+12 \n" ); document.write( "----- \n" ); document.write( "Simplify: \n" ); document.write( "y = 3x^2 - 2x +4 \n" ); document.write( "----- \n" ); document.write( "Vertex occurs where x = -b/2a = 2/(6) = 1/3 \n" ); document.write( "----- \n" ); document.write( "f(1/3) = 3(1/9) - (2/3) + 12/3 = 11/3 \n" ); document.write( "--- \n" ); document.write( "Plot the vertex at (1/3 , 11,3) \n" ); document.write( "--- \n" ); document.write( "y-intercept = f(0) = 4 \n" ); document.write( "Plot (0,4) \n" ); document.write( "---- \n" ); document.write( "Sketch a parabola thru those points opening upward.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |