document.write( "Question 706989: How do I graph the relation 3y= 9x^2-6x+12? \n" ); document.write( "
Algebra.Com's Answer #435456 by stanbon(75887)\"\" \"About 
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graph the relation 3y= 9x^2-6x+12
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\n" ); document.write( "Simplify:
\n" ); document.write( "y = 3x^2 - 2x +4
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\n" ); document.write( "Vertex occurs where x = -b/2a = 2/(6) = 1/3
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\n" ); document.write( "f(1/3) = 3(1/9) - (2/3) + 12/3 = 11/3
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\n" ); document.write( "Plot the vertex at (1/3 , 11,3)
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\n" ); document.write( "y-intercept = f(0) = 4
\n" ); document.write( "Plot (0,4)
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\n" ); document.write( "Sketch a parabola thru those points opening upward.\r
\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C3x%5E2-2x%2B4%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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