document.write( "Question 62449: Find the point P on the plane 0x+1y-3z=8 closest to the point Q(2,-3,3).\r
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Algebra.Com's Answer #43545 by venugopalramana(3286)\"\" \"About 
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Find the point P on the plane 0x+1y-3z=8 closest to the point Q(2,-3,3).
\n" ); document.write( "P = ( , , )?????(p,q,r) say
\n" ); document.write( "it on plane.hence
\n" ); document.write( "q-3r=8...............1
\n" ); document.write( "PQ is perpenicular to plane...or parallel to its normal
\n" ); document.write( "drs of plane = (0,1,-3)
\n" ); document.write( "drs of PQ = [p-2,q+3,r-3]
\n" ); document.write( "(p-2)/0 = (q+3)/1 = (r-3)/-3
\n" ); document.write( "p=2
\n" ); document.write( "r-3 = -3(q+3)=-3q-9
\n" ); document.write( "3q+r=-6..............2
\n" ); document.write( "3*eqn.1-en.2
\n" ); document.write( "-10r=30
\n" ); document.write( "r=-3
\n" ); document.write( "3q=-3
\n" ); document.write( "q=-1
\n" ); document.write( "hence p is (2,-1,-3)\r
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